Shookville, Georgia

United States

City34.9117° N, 85.0863° W

Found in Georgia, United States, Shookville is a city.

Population—

ProvinceGeorgia

Coordinates34.9117° N, 85.0863° W

Elevation236 m

CountryUnited States

Map

About Shookville

Shookville is located at coordinates 34.91° N, 85.09° W, in the Northern Hemisphere. It belongs to the Georgia administrative division of United States. The city sits at an elevation of 236 meters above sea level.

Cities in Georgia

Shookville is located in the Georgia province of United States. Other cities in the region include Atlanta, Columbus, Savannah.

Atlanta510,823 Columbus206,922 Savannah147,780 Athens127,315 South Fulton107,436 Sandy Springs105,330 Roswell94,501 Macon91,351 Johns Creek83,335 Albany74,843

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Frequently Asked Questions

What province or state is Shookville in?

Shookville is located in Georgia, United States.

Where is Shookville located?

Shookville is located at coordinates 34.91° N, 85.09° W in Georgia, United States. It sits at an elevation of 236 meters above sea level.

Structured data for Shookville, United States is available through Bamwor, a global dataset covering countries and millions of cities.

This data can be accessed via:
– Bamwor REST API: https://bamwor.com/api/v1/cities/4222679
– Bamwor MCP Server for AI agents and real-time retrieval

API Documentation →MCP Server →

GET /api/v1/cities/4222679

Source: Bamwor World Encyclopedia — GeoNames (CC BY 4.0)