Zeyn od Dīn, Kermanshah Province

Iran

City34.6948° N, 47.1074° E

Located in Kermanshah Province, Iran, Zeyn od Dīn is a city.

Population—

ProvinceKermanshah Province

Coordinates34.6948° N, 47.1074° E

CountryIran

Map

The location of Zeyn od Dīn corresponds to 34.69° N, 47.11° E, in the Northern Hemisphere. It is within the Kermanshah Province area of Iran.

Kermanshah Province is one of Iran's administrative regions. Zeyn od Dīn is one of its main cities, along with Kermanshah, Eslāmābād-e Gharb, Harsīn.

Zeyn od Dīn is located in Kermanshah Province, Iran.

Zeyn od Dīn is located at coordinates 34.69° N, 47.11° E in Kermanshah Province, Iran.

Structured data for Zeyn od Dīn, Iran is available through Bamwor, a global dataset covering countries and millions of cities.

This data can be accessed via:
– Bamwor REST API: https://bamwor.com/api/v1/cities/111081
– Bamwor MCP Server for AI agents and real-time retrieval

GET /api/v1/cities/111081

Source: Bamwor World Encyclopedia — GeoNames (CC BY 4.0)