← Back to Cities of IranKhān ‘Abdāl, Razavi Khorasan
Iran
City37.1056° N, 59.6193° E
In Razavi Khorasan, Iran, Khān ‘Abdāl is a city.
Population—
ProvinceRazavi Khorasan
Coordinates37.1056° N, 59.6193° E
CountryIran
About Khān ‘Abdāl
Khān ‘Abdāl can be found at 37.11° N, 59.62° E in the Northern Hemisphere. It is part of the Razavi Khorasan division in Iran.
Cities in Razavi Khorasan
Razavi Khorasan is one of Iran's administrative regions. Khān ‘Abdāl is one of its main cities, along with Mashhad, Marāgheh, Sabzevar.
Mashhad2,307,177Marāgheh262,604Sabzevar226,183Neyshābūr220,929Torbat-e Ḩeydarīyeh125,633Qūchān111,752Kāshmar96,151Torbat-e Jām58,928Chenārān46,940Sarakhs46,499 Nearby Cities
Within 25 km of Khān ‘Abdāl, 20 populated places have been registered.
Explore Iran
Largest cities in Iran
#1 Tehran7,153,309#2 Mashhad2,307,177#3 Isfahan1,547,164#4 Karaj1,448,075#5 Tabriz1,424,641 Frequently Asked Questions
What province or state is Khān ‘Abdāl in?
Khān ‘Abdāl is located in Razavi Khorasan, Iran.
Where is Khān ‘Abdāl located?
Khān ‘Abdāl is located at coordinates 37.11° N, 59.62° E in Razavi Khorasan, Iran.
Source: Bamwor World Encyclopedia — GeoNames (CC BY 4.0)