France
Saint-André-de-Bohon, in Normandy, France, is a city. Its population is 270.
The geographic coordinates of Saint-André-de-Bohon are 49.23° N, 1.25° W, placing it in the Northern Hemisphere. Administratively, it falls within Normandy, France.
Out of 81,594 localities in France, Saint-André-de-Bohon ranks #21,868 with 270 inhabitants.
Within the Normandy region of France, Saint-André-de-Bohon stands alongside cities like Le Havre, Rouen, Caen. Saint-André-de-Bohon has 270 inhabitants.
Saint-André-de-Bohon has 20 nearby cities and towns within a 25 km radius.
Saint-André-de-Bohon has a population of 270. It ranks #21,868 in France by population.
Saint-André-de-Bohon is located in Normandy, France.
Saint-André-de-Bohon is located at coordinates 49.23° N, 1.25° W in Normandy, France.
Source: Bamwor World Encyclopedia — GeoNames (CC BY 4.0)