Le Teilleul, Normandy

France

City48.5376° N, 0.8730° W

Situated in Normandy, France, Le Teilleul is a city. It has a population of 1,422.

Population1,422

ProvinceNormandy

Coordinates48.5376° N, 0.8730° W

CountryFrance

Rank in France#6,588 of 81,594

Map

About Le Teilleul

Geographically, Le Teilleul is positioned at 48.54° N, 0.87° W, within the Northern Hemisphere. It is administered as part of Normandy, France.

The population of Le Teilleul is 1,422, placing it at position #6,588 among 81,594 localities in France.

Cities in Normandy

Le Teilleul is located in the Normandy province of France. Other cities in the region include Le Havre, Rouen, Caen. Le Teilleul has 1,422 inhabitants.

Le Havre185,972 Rouen116,331 Caen110,624 Évreux57,795 Dieppe35,707 Alençon30,786 Sotteville-lès-Rouen30,619 Saint-Étienne-du-Rouvray28,953 Cherbourg26,655 Le Grand-Quevilly26,522

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#1 Paris2,138,551 #2 Marseille877,215 #3 Lyon520,774 #4 Toulouse511,684 #5 Nice342,669

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Frequently Asked Questions

What is the population of Le Teilleul?

Le Teilleul has a population of 1,422. It ranks #6,588 in France by population.

What province or state is Le Teilleul in?

Le Teilleul is located in Normandy, France.

Where is Le Teilleul located?

Le Teilleul is located at coordinates 48.54° N, 0.87° W in Normandy, France.

Le Teilleul, France data is included in the Bamwor global dataset, a structured database used by developers and AI systems.

Access this data programmatically via the Bamwor API:
https://bamwor.com/api/v1/cities/2999251

For AI-native workflows, the Bamwor MCP Server provides direct structured access.

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Source: Bamwor World Encyclopedia — GeoNames (CC BY 4.0)