Ukraine
Semidvor'e, in Crimea, Ukraine, is a city. Its population is 102.
The geographic coordinates of Semidvor'e are 44.72° N, 34.47° E, placing it in the Northern Hemisphere. Administratively, it falls within Crimea, Ukraine. Its elevation is 58 meters.
Out of 33,534 localities in Ukraine, Semidvor'e ranks #7,538 with 102 inhabitants.
Within the Crimea region of Ukraine, Semidvor'e stands alongside cities like Simferopol, Kerch, Yevpatoriya. Semidvor'e has 102 inhabitants.
Semidvor'e has 20 nearby cities and towns within a 25 km radius.
Semidvor'e has a population of 102. It ranks #7,538 in Ukraine by population.
Semidvor'e is located in Crimea, Ukraine.
Semidvor'e is located at coordinates 44.72° N, 34.47° E in Crimea, Ukraine. It sits at an elevation of 58 meters above sea level.
Source: Bamwor World Encyclopedia — GeoNames (CC BY 4.0)