Valea Seacă, Prahova

Romania

City45.1039° N, 26.2678° E

Valea Seacă is a city in Prahova, Romania. The recorded population is 157.

Population157

ProvincePrahova

Coordinates45.1039° N, 26.2678° E

CountryRomania

Rank in Romania#11,044 of 18,248

Map

At coordinates 45.10° N, 26.27° E, Valea Seacă lies in the Northern Hemisphere. The city belongs to Prahova in Romania.

Valea Seacă has 157 inhabitants, making it the #11,044 most populated locality in Romania out of 18,248 registered.

The Prahova region of Romania is home to Valea Seacă and other cities such as Ploieşti, Câmpina, Băicoi. Valea Seacă has 157 inhabitants.

The area surrounding Valea Seacă includes 20 nearby cities and towns.

Valea Seacă has a population of 157. It ranks #11,044 in Romania by population.

Valea Seacă is located in Prahova, Romania.

Valea Seacă is located at coordinates 45.10° N, 26.27° E in Prahova, Romania.

The data for Valea Seacă, Romania is part of the Bamwor structured dataset, covering 261 countries and over 13 million cities worldwide.

Developers can access Valea Seacă, Romania data programmatically via the Bamwor REST API:
https://bamwor.com/api/v1/cities/663428

AI agents can access Valea Seacă, Romania data via the Bamwor MCP Server for real-time structured retrieval.

GET /api/v1/cities/663428

Source: Bamwor World Encyclopedia — GeoNames (CC BY 4.0)