Teiușu, Vâlcea County

Romania

Neighborhood45.0927° N, 24.2396° E

Found in Vâlcea County, Romania, Teiușu is a neighborhood. It has a population of 526.

Population526

ProvinceVâlcea County

Coordinates45.0927° N, 24.2396° E

CountryRomania

Rank in Romania#6,813 of 18,248

Map

About Teiușu

Teiușu is located at coordinates 45.09° N, 24.24° E, in the Northern Hemisphere. It belongs to the Vâlcea County administrative division of Romania.

Teiușu is the #6,813 largest locality in Romania by population, with 526 people.

Cities in Vâlcea County

Teiușu is located in the Vâlcea County province of Romania. Other cities in the region include Râmnicu Vâlcea, Drăgăşani, Băbeni. Teiușu has 526 inhabitants.

Râmnicu Vâlcea93,151 Drăgăşani20,630 Băbeni9,350 Călimăneşti8,485 Horezu6,743 Brezoi6,668 Mihăeşti6,263 Bălceşti5,683 Berbeşti5,606 Budeşti5,362

Nearby Cities

There are 20 cities and towns within 25 km of Teiușu.

Explore Romania

Romania profile All cities of Romania World rankings Compare countries

Largest cities in Romania

#1 Bucharest1,877,155 #2 Sector 3385,439 #3 Iaşi378,954 #4 Sector 6367,760 #5 Constanţa317,832

Frequently Asked Questions

What is the population of Teiușu?

Teiușu has a population of 526. It ranks #6,813 in Romania by population.

What province or state is Teiușu in?

Teiușu is located in Vâlcea County, Romania.

Where is Teiușu located?

Teiușu is located at coordinates 45.09° N, 24.24° E in Vâlcea County, Romania.

Teiușu, Romania data is included in the Bamwor global dataset, a structured database used by developers and AI systems.

Access this data programmatically via the Bamwor API:
https://bamwor.com/api/v1/cities/665311

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Source: Bamwor World Encyclopedia — GeoNames (CC BY 4.0)