Teiuș, Bacău County

Romania

City46.3225° N, 26.9703° E

In Bacău County, Romania, Teiuș is a city. It is home to 306 people.

Population306

ProvinceBacău County

Coordinates46.3225° N, 26.9703° E

CountryRomania

Rank in Romania#9,055 of 18,248

Map

About Teiuș

Teiuș can be found at 46.32° N, 26.97° E in the Northern Hemisphere. It is part of the Bacău County division in Romania.

With a population of 306, Teiuș ranks #9,055 among the 18,248 cities and localities registered in Romania.

Cities in Bacău County

Bacău County is one of Romania's administrative regions. Teiuș is one of its main cities, along with Bacău, Moineşti, Comăneşti. Teiuș has 306 inhabitants.

Bacău136,087 Moineşti23,981 Comăneşti23,729 Buhuşi18,395 Dărmăneşti14,290 Târgu Ocna13,127 Dofteana10,785 Nicolae Bălcescu10,140 Sascut10,031 Oituz9,596

Nearby Cities

Within 25 km of Teiuș, 20 populated places have been registered.

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Largest cities in Romania

#1 Bucharest1,877,155 #2 Sector 3385,439 #3 Iaşi378,954 #4 Sector 6367,760 #5 Constanţa317,832

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Frequently Asked Questions

What is the population of Teiuș?

Teiuș has a population of 306. It ranks #9,055 in Romania by population.

What province or state is Teiuș in?

Teiuș is located in Bacău County, Romania.

Where is Teiuș located?

Teiuș is located at coordinates 46.32° N, 26.97° E in Bacău County, Romania.

Teiuș, Romania data is included in the Bamwor global dataset, a structured database used by developers and AI systems.

Access this data programmatically via the Bamwor API:
https://bamwor.com/api/v1/cities/665317

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Source: Bamwor World Encyclopedia — GeoNames (CC BY 4.0)