Seuca, Gorj County

Romania

City45.0102° N, 23.0334° E

Situated in Gorj County, Romania, Seuca is a city. It has a population of 227.

Population227

ProvinceGorj County

Coordinates45.0102° N, 23.0334° E

CountryRomania

Rank in Romania#10,011 of 18,248

Map

Geographically, Seuca is positioned at 45.01° N, 23.03° E, within the Northern Hemisphere. It is administered as part of Gorj County, Romania.

The population of Seuca is 227, placing it at position #10,011 among 18,248 localities in Romania.

Seuca is located in the Gorj County province of Romania. Other cities in the region include Târgu Jiu, Motru, Rovinari. Seuca has 227 inhabitants.

Seuca has a population of 227. It ranks #10,011 in Romania by population.

Seuca is located in Gorj County, Romania.

Seuca is located at coordinates 45.01° N, 23.03° E in Gorj County, Romania.

The data for Seuca, Romania is part of the Bamwor structured dataset, covering 261 countries and over 13 million cities worldwide.

Developers can access Seuca, Romania data programmatically via the Bamwor REST API:
https://bamwor.com/api/v1/cities/667323

AI agents can access Seuca, Romania data via the Bamwor MCP Server for real-time structured retrieval.

GET /api/v1/cities/667323

Source: Bamwor World Encyclopedia — GeoNames (CC BY 4.0)