Seaca, Bacău County

Romania

City46.3311° N, 26.5080° E

In Bacău County, Romania, Seaca is a city. It is home to 455 people.

Population455

ProvinceBacău County

Coordinates46.3311° N, 26.5080° E

CountryRomania

Rank in Romania#7,417 of 18,248

Map

About Seaca

Seaca can be found at 46.33° N, 26.51° E in the Northern Hemisphere. It is part of the Bacău County division in Romania.

With a population of 455, Seaca ranks #7,417 among the 18,248 cities and localities registered in Romania.

Cities in Bacău County

Bacău County is one of Romania's administrative regions. Seaca is one of its main cities, along with Bacău, Moineşti, Comăneşti. Seaca has 455 inhabitants.

Bacău136,087 Moineşti23,981 Comăneşti23,729 Buhuşi18,395 Dărmăneşti14,290 Târgu Ocna13,127 Dofteana10,785 Nicolae Bălcescu10,140 Sascut10,031 Oituz9,596

Explore Romania

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Largest cities in Romania

#1 Bucharest1,877,155 #2 Sector 3385,439 #3 Iaşi378,954 #4 Sector 6367,760 #5 Constanţa317,832

Frequently Asked Questions

What is the population of Seaca?

Seaca has a population of 455. It ranks #7,417 in Romania by population.

What province or state is Seaca in?

Seaca is located in Bacău County, Romania.

Where is Seaca located?

Seaca is located at coordinates 46.33° N, 26.51° E in Bacău County, Romania.

Seaca, Romania data is included in the Bamwor global dataset, a structured database used by developers and AI systems.

Access this data programmatically via the Bamwor API:
https://bamwor.com/api/v1/cities/667541

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Source: Bamwor World Encyclopedia — GeoNames (CC BY 4.0)