Romania
Found in Hunedoara County, Romania, Sânpetru is a city. It has a population of 304.
Sânpetru is located at coordinates 45.56° N, 22.92° E, in the Northern Hemisphere. It belongs to the Hunedoara County administrative division of Romania.
Sânpetru is the #9,075 largest locality in Romania by population, with 304 people.
Sânpetru is located in the Hunedoara County province of Romania. Other cities in the region include Hunedoara, Deva, Petroşani. Sânpetru has 304 inhabitants.
There are 20 cities and towns within 25 km of Sânpetru.
Sânpetru has a population of 304. It ranks #9,075 in Romania by population.
Sânpetru is located in Hunedoara County, Romania.
Sânpetru is located at coordinates 45.56° N, 22.92° E in Hunedoara County, Romania.
Source: Bamwor World Encyclopedia — GeoNames (CC BY 4.0)