Obislavu, Vâlcea County

Romania

City44.9098° N, 23.7900° E

Found in Vâlcea County, Romania, Obislavu is a city. It has a population of 196.

Population196

ProvinceVâlcea County

Coordinates44.9098° N, 23.7900° E

CountryRomania

Rank in Romania#10,466 of 18,248

Map

About Obislavu

Obislavu is located at coordinates 44.91° N, 23.79° E, in the Northern Hemisphere. It belongs to the Vâlcea County administrative division of Romania.

Obislavu is the #10,466 largest locality in Romania by population, with 196 people.

Cities in Vâlcea County

Obislavu is located in the Vâlcea County province of Romania. Other cities in the region include Râmnicu Vâlcea, Drăgăşani, Băbeni. Obislavu has 196 inhabitants.

Râmnicu Vâlcea93,151 Drăgăşani20,630 Băbeni9,350 Călimăneşti8,485 Horezu6,743 Brezoi6,668 Mihăeşti6,263 Bălceşti5,683 Berbeşti5,606 Budeşti5,362

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Largest cities in Romania

#1 Bucharest1,877,155 #2 Sector 3385,439 #3 Iaşi378,954 #4 Sector 6367,760 #5 Constanţa317,832

Frequently Asked Questions

What is the population of Obislavu?

Obislavu has a population of 196. It ranks #10,466 in Romania by population.

What province or state is Obislavu in?

Obislavu is located in Vâlcea County, Romania.

Where is Obislavu located?

Obislavu is located at coordinates 44.91° N, 23.79° E in Vâlcea County, Romania.

Structured data for Obislavu, Romania is available through Bamwor, a global dataset covering countries and millions of cities.

This data can be accessed via:
– Bamwor REST API: https://bamwor.com/api/v1/cities/672063
– Bamwor MCP Server for AI agents and real-time retrieval

API Documentation →MCP Server →

GET /api/v1/cities/672063

Source: Bamwor World Encyclopedia — GeoNames (CC BY 4.0)