← Back to Cities of RomaniaOanțu, Neamț County
Romania
City46.9097° N, 26.1989° E
Oanțu is a city situated in Neamț County, Romania. Its population is 1,009.
Population1,009
ProvinceNeamț County
Coordinates46.9097° N, 26.1989° E
CountryRomania
Rank in Romania#4,274 of 18,248
About Oanțu
Oanțu is situated at 46.91° N, 26.20° E in the Northern Hemisphere. It falls under the Neamț County region of Romania.
Oanțu occupies position #4,274 by population in Romania, with 1,009 inhabitants across 18,248 registered cities.
Cities in Neamț County
Within the Neamț County region of Romania, Oanțu stands alongside cities like Piatra Neamţ, Roman, Târgu Neamţ. Oanțu has 1,009 inhabitants.
Piatra Neamţ102,688Roman67,819Târgu Neamţ20,473Săbăoani10,218Borleşti8,965Roznov8,688Pipirig8,569Bicaz8,340Tămăşeni8,292Răuceşti8,204 Nearby Cities
In the vicinity of Oanțu, there are 20 cities and towns within 25 km.
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Frequently Asked Questions
What is the population of Oanțu?
Oanțu has a population of 1,009. It ranks #4,274 in Romania by population.
What province or state is Oanțu in?
Oanțu is located in Neamț County, Romania.
Where is Oanțu located?
Oanțu is located at coordinates 46.91° N, 26.20° E in Neamț County, Romania.
Source: Bamwor World Encyclopedia — GeoNames (CC BY 4.0)