Located in Hunedoara County, Romania, Leauț is a city. It is home to 73 people.
Population73
ProvinceHunedoara County
Coordinates46.2333° N, 22.6833° E
CountryRomania
Rank in Romania#12,182 of 18,248
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About Leauț
The location of Leauț corresponds to 46.23° N, 22.68° E, in the Northern Hemisphere. It is within the Hunedoara County area of Romania.
Among the 18,248 cities of Romania, Leauț holds position #12,182 with a population of 73.
Cities in Hunedoara County
Hunedoara County is one of Romania's administrative regions. Leauț is one of its main cities, along with Hunedoara, Deva, Petroşani. Leauț has 73 inhabitants.