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  5. /Ferestrău-Oituz
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Ferestrău-Oituz, Bacău County

Romania

City46.2025° N, 26.5763° E

Located in Bacău County, Romania, Ferestrău-Oituz is a city. It is home to 1,036 people.

Population1,036
ProvinceBacău County
Coordinates46.2025° N, 26.5763° E
CountryRomania
Rank in Romania#4,174 of 18,248

Map

About Ferestrău-Oituz

The location of Ferestrău-Oituz corresponds to 46.20° N, 26.58° E, in the Northern Hemisphere. It is within the Bacău County area of Romania.

Among the 18,248 cities of Romania, Ferestrău-Oituz holds position #4,174 with a population of 1,036.

Cities in Bacău County

Bacău County is one of Romania's administrative regions. Ferestrău-Oituz is one of its main cities, along with Bacău, Moineşti, Comăneşti. Ferestrău-Oituz has 1,036 inhabitants.

Bacău136,087Moineşti23,981Comăneşti23,729Buhuşi18,395Dărmăneşti14,290Târgu Ocna13,127Dofteana10,785Nicolae Bălcescu10,140Sascut10,031Oituz9,596

Nearby Cities

Around Ferestrău-Oituz, 20 nearby populated places have been recorded within 25 km.

●
CălcâiCity · 452 inhab.
1.9 km
●
OituzProvincial capital · 9,596 inhab.
3.1 km
●
HătmaniCity
3.1 km
●
MargineaCity · 684 inhab.
4.9 km
●
CireșoaiaCity · 1,811 inhab.
5.5 km
●
CerdacNeighborhood · 1,571 inhab.
6.1 km
●
BahnaCity · 594 inhab.
6.3 km
●
NicoreștiCity · 902 inhab.
6.7 km
●
Gura SlăniculuiNeighborhood
7.2 km
●
Satu NouCity · 1,699 inhab.
7.6 km
●
TiseştiNeighborhood
7.8 km
●
PârgăreştiProvincial capital · 4,798 inhab.
7.8 km
●
Slănic-MoldovaProvincial capital · 4,955 inhab.
8.2 km
●
Pârâu BoghiiCity · 336 inhab.
8.4 km
●
BogdăneştiProvincial capital · 2,740 inhab.
8.4 km
●
HârjaCity · 450 inhab.
8.7 km
●
PoieniCity · 720 inhab.
9 km
●
Târgu OcnaProvincial capital · 13,127 inhab.
9 km
●
MosoareleNeighborhood
9 km
●
PăcureleNeighborhood
9 km

Explore Romania

Romania profileAll cities of RomaniaWorld rankingsCompare countries

Largest cities in Romania

#1 Bucharest1,877,155#2 Sector 3385,439#3 Iaşi378,954#4 Sector 6367,760#5 Constanţa317,832
Search People Ferestrău-Oituz →

Frequently Asked Questions

What is the population of Ferestrău-Oituz?

Ferestrău-Oituz has a population of 1,036. It ranks #4,174 in Romania by population.

What province or state is Ferestrău-Oituz in?

Ferestrău-Oituz is located in Bacău County, Romania.

Where is Ferestrău-Oituz located?

Ferestrău-Oituz is located at coordinates 46.20° N, 26.58° E in Bacău County, Romania.

Ferestrău-Oituz, Romania data is included in the Bamwor global dataset, a structured database used by developers and AI systems.

Access this data programmatically via the Bamwor API:
https://bamwor.com/api/v1/cities/678337

For AI-native workflows, the Bamwor MCP Server provides direct structured access.

API Documentation →MCP Server →
GET /api/v1/cities/678337

Source: Bamwor World Encyclopedia — GeoNames (CC BY 4.0)