Feleacu, Cluj County

Romania

Provincial capital46.7167° N, 23.6167° E

Situated in Cluj County, Romania, Feleacu is a provincial capital. It has a population of 3,764.

Population3,764

ProvinceCluj County

Coordinates46.7167° N, 23.6167° E

CountryRomania

Rank in Romania#1,294 of 18,248

Map

Geographically, Feleacu is positioned at 46.72° N, 23.62° E, within the Northern Hemisphere. It is administered as part of Cluj County, Romania.

The population of Feleacu is 3,764, placing it at position #1,294 among 18,248 localities in Romania.

Feleacu is located in the Cluj County province of Romania. Other cities in the region include Cluj-Napoca, Turda, Dej. Feleacu has 3,764 inhabitants.

20 populated places are found within 25 km of Feleacu.

Feleacu has a population of 3,764. It ranks #1,294 in Romania by population.

Feleacu is located in Cluj County, Romania.

Feleacu is located at coordinates 46.72° N, 23.62° E in Cluj County, Romania.

Structured data for Feleacu, Romania is available through Bamwor, a global dataset covering countries and millions of cities.

This data can be accessed via:
– Bamwor REST API: https://bamwor.com/api/v1/cities/678355
– Bamwor MCP Server for AI agents and real-time retrieval

GET /api/v1/cities/678355

Source: Bamwor World Encyclopedia — GeoNames (CC BY 4.0)