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  5. /Švikščionys
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Švikščionys, Utena

Lithuania

City55.5571° N, 26.5962° E

In Utena, Lithuania, Švikščionys is a city.

Population—
ProvinceUtena
Coordinates55.5571° N, 26.5962° E
CountryLithuania

Map

About Švikščionys

Švikščionys can be found at 55.56° N, 26.60° E in the Northern Hemisphere. It is part of the Utena division in Lithuania.

Cities in Utena

Utena is one of Lithuania's administrative regions. Švikščionys is one of its main cities, along with Utena, Visaginas, Anykščiai.

Utena25,397Visaginas18,024Anykščiai10,575Molėtai7,243Zarasai6,051Ignalina5,106Dūkštas888Dusetos833Kavarskas755Leliūnai483

Nearby Cities

Within 25 km of Švikščionys, 20 populated places have been registered.

●
VarniškiaiCity
1.4 km
●
BerniūnaiCity
1.9 km
●
GalilaukėCity
1.9 km
●
StanionysCity
1.9 km
●
Beržininkai IICity
1.9 km
●
KalnežerisCity
2.2 km
●
MačionysCity
2.2 km
●
VosyliškėsCity
2.3 km
●
GritunyCity
2.4 km
●
BalandiškėCity
2.5 km
●
GaidėCity
2.7 km
●
HireyshyCity
2.8 km
●
NurvyanyCity
3.3 km
●
SkryteliaiCity
3.6 km
●
KukutėnaiCity
4 km
●
ČepukaiCity
4 km
●
MatselyanyCity
4.1 km
●
VilkaragisCity
4.2 km
●
ŠaškaiCity
4.3 km
●
SerbiejiškėCity
4.6 km

Explore Lithuania

Lithuania profileAll cities of LithuaniaWorld rankingsCompare countries

Largest cities in Lithuania

#1 Vilnius542,366#2 Kaunas289,380#3 Klaipėda172,292#4 Šiauliai99,462#5 Panevėžys85,885
Search People Švikščionys →

Frequently Asked Questions

What province or state is Švikščionys in?

Švikščionys is located in Utena, Lithuania.

Where is Švikščionys located?

Švikščionys is located at coordinates 55.56° N, 26.60° E in Utena, Lithuania.

Švikščionys, Lithuania data is included in the Bamwor global dataset, a structured database used by developers and AI systems.

Access this data programmatically via the Bamwor API:
https://bamwor.com/api/v1/cities/11291005

For AI-native workflows, the Bamwor MCP Server provides direct structured access.

API Documentation →MCP Server →
GET /api/v1/cities/11291005

Source: Bamwor World Encyclopedia — GeoNames (CC BY 4.0)