← Back to Cities of IndiaSheopāl Singh, Uttar Pradesh
India
City27.0093° N, 82.4638° E
In Uttar Pradesh, India, Sheopāl Singh is a city.
Population—
ProvinceUttar Pradesh
Coordinates27.0093° N, 82.4638° E
CountryIndia
About Sheopāl Singh
Sheopāl Singh can be found at 27.01° N, 82.46° E in the Northern Hemisphere. It is part of the Uttar Pradesh division in India.
Cities in Uttar Pradesh
Uttar Pradesh is one of India's administrative regions. Sheopāl Singh is one of its main cities, along with Kanpur, Lucknow, Agra.
Kanpur2,823,249Lucknow2,472,011Agra1,430,055Meerut1,223,184Ghāziābād1,199,191Varanasi1,164,404Prayagraj1,073,438Alīgarh753,207Bareilly745,435Morādābād721,139 Nearby Cities
Within 25 km of Sheopāl Singh, 20 populated places have been registered.
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Largest cities in India
#1 Mumbai12,691,836#2 Delhi11,034,555#3 Bengaluru8,495,492#4 Hyderabad6,993,262#5 Ahmedabad6,357,693 Frequently Asked Questions
What province or state is Sheopāl Singh in?
Sheopāl Singh is located in Uttar Pradesh, India.
Where is Sheopāl Singh located?
Sheopāl Singh is located at coordinates 27.01° N, 82.46° E in Uttar Pradesh, India.
Source: Bamwor World Encyclopedia — GeoNames (CC BY 4.0)