Lippendorf, Saxony

Germany

City51.1739° N, 12.3719° E

Situated in Saxony, Germany, Lippendorf is a city.

Population—

ProvinceSaxony

Coordinates51.1739° N, 12.3719° E

CountryGermany

Map

Geographically, Lippendorf is positioned at 51.17° N, 12.37° E, within the Northern Hemisphere. It is administered as part of Saxony, Germany.

Lippendorf is located in the Saxony province of Germany. Other cities in the region include Dresden, Leipzig, Chemnitz.

Lippendorf is located in Saxony, Germany.

Lippendorf is located at coordinates 51.17° N, 12.37° E in Saxony, Germany.

Structured data for Lippendorf, Germany is available through Bamwor, a global dataset covering countries and millions of cities.

This data can be accessed via:
– Bamwor REST API: https://bamwor.com/api/v1/cities/2876915
– Bamwor MCP Server for AI agents and real-time retrieval

GET /api/v1/cities/2876915

Source: Bamwor World Encyclopedia — GeoNames (CC BY 4.0)