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  5. /Heiniliang
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Heiniliang, Gansu

China

City36.2240° N, 108.0600° E

Heiniliang, in Gansu, China, is a city.

Population—
ProvinceGansu
Coordinates36.2240° N, 108.0600° E
CountryChina

Map

About Heiniliang

The geographic coordinates of Heiniliang are 36.22° N, 108.06° E, placing it in the Northern Hemisphere. Administratively, it falls within Gansu, China.

Cities in Gansu

Within the Gansu region of China, Heiniliang stands alongside cities like Lanzhou, Qingyang, Tianshui.

Lanzhou3,000,000Qingyang2,125,400Tianshui1,212,791Wuwei1,010,295Zhangye507,433Pingliang504,848Jiuquan428,346Dingxi420,614Baiyin294,400Linxia Chengguanzhen274,466

Nearby Cities

Heiniliang has 20 nearby cities and towns within a 25 km radius.

●
NiujiachaCity
1.6 km
●
YaoziyuanCity
2.2 km
●
ShigouyuanCity
2.2 km
●
LijiayuanCity
2.3 km
●
NiujiayuanCity
3 km
●
ZhongyuanCity
3.5 km
●
WangnanyuanCity
3.6 km
●
ShangzhuangCity
4.1 km
●
LishuyuanCity
4.1 km
●
Liushu YaoxianCity
4.3 km
●
ShizuiziCity
4.8 km
●
AnzhuangCity
5 km
●
JiziwanCity
5.1 km
●
XiagoumenCity
5.1 km
●
ZhangzhuangCity
5.7 km
●
HuangyuanCity
5.9 km
●
ShangnanzhangwanCity
6 km
●
CaonangouCity
6 km
●
ChenghaoCity
6.5 km
●
ShuipingyuanCity
6.6 km

Explore China

China profileAll cities of ChinaWorld rankingsCompare countries

Largest cities in China

#1 Shanghai24,874,500#2 Beijing18,960,744#3 Shenzhen17,494,398#4 Guangzhou16,096,724#5 Chengdu13,568,357
Search People Heiniliang →

Frequently Asked Questions

What province or state is Heiniliang in?

Heiniliang is located in Gansu, China.

Where is Heiniliang located?

Heiniliang is located at coordinates 36.22° N, 108.06° E in Gansu, China.

Structured data for Heiniliang, China is available through Bamwor, a global dataset covering countries and millions of cities.

This data can be accessed via:
– Bamwor REST API: https://bamwor.com/api/v1/cities/10737558
– Bamwor MCP Server for AI agents and real-time retrieval

API Documentation →MCP Server →
GET /api/v1/cities/10737558

Source: Bamwor World Encyclopedia — GeoNames (CC BY 4.0)