Sevost’yanovichi, Mogilev

Belarus

City53.9041° N, 30.1661° E

Sevost’yanovichi is a city situated in Mogilev, Belarus.

Population—

ProvinceMogilev

Coordinates53.9041° N, 30.1661° E

CountryBelarus

Map

Sevost’yanovichi is situated at 53.90° N, 30.17° E in the Northern Hemisphere. It falls under the Mogilev region of Belarus.

Within the Mogilev region of Belarus, Sevost’yanovichi stands alongside cities like Mahilyow, Bobruysk, Osipovichi.

Sevost’yanovichi is located in Mogilev, Belarus.

Sevost’yanovichi is located at coordinates 53.90° N, 30.17° E in Mogilev, Belarus.

Structured data for Sevost’yanovichi, Belarus is available through Bamwor, a global dataset covering countries and millions of cities.

This data can be accessed via:
– Bamwor REST API: https://bamwor.com/api/v1/cities/622370
– Bamwor MCP Server for AI agents and real-time retrieval

GET /api/v1/cities/622370

Source: Bamwor World Encyclopedia — GeoNames (CC BY 4.0)